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Department of Engineering |
| University of Cambridge > Engineering Department > Research > Structures Group > Research Students |
At the simplest level, a tensegrity structure can be made with one orbit of cables and one orbit of struts. Our aim is to show how the local site symmetry can be used to solve the equilibrium of nodal configurations of such simple tensegrity structures. Here, we consider the point group symmetry, Ih , with site symmetry, Cs .
The point groups, Ih have 5-fold axes of symmetry. These symmetry groups contain twelve 5-fold, twenty 3-fold, and fifteen 2-fold axes and has 120 symmetry operations. They are related to the symmetry of the icosahedron. The site symmetry, Cs , will have a plane of reflection.
If we choose to have:
1) site symmetry, Cs : σa ;
2) a strut connecting node E to node C 2a with tension coefficient t s ; and
3) a cable connecting nodes E to node C + 51, and node C - 51 with tension coefficient t t ,
then solution t t / t s = - 2.62 gives the tensegrity structure I h : Cs1 with an orbit of 60 nodes.
If we choose to have:
1) site symmetry, Cs : σg ;
2) a strut connecting node E to node σc with tension coefficient t s ; and
3) a cable connecting nodes E to node C+51, and node C-51 with tension coefficient t t ,
then solution t t / t s = - 1.81 gives the tensegrity structure I h : Cs2 with an orbit of 60 nodes.
If we choose to have:
1) site symmetry, Cs : σc ;
2) a strut connecting node E to node C 2d with tension coefficient t s ; and
3) a cable connecting nodes E to node C + 51, and node C - 51 with tension coefficient t t ,
then solution t t / t s = - 3.93 gives the tensegrity structure I h : Cs3 with an orbit of 60 nodes.